$(a_1^2+a_2^2+\cdots+a_n^2)(b_1^2+b_2^2+\cdots+b_n^2)\ge(a_1b_1+a_2b_2+\cdots+a_nb_n)^2$ ---- $a_i,b_i\in\mathbb{R}$ $\left(\sum_{i=1}^{n}a_i^2\right)^{\frac12} \left(\sum_{i=1}^{n}b_i^2\right)^{\frac12} \ge \left| \sum_{i=1}^{n}a_ib_i \right|$ ---- [[벡터,vector]]로 나타내면 $|\vec{x}| |\vec{y}| \ge |\vec{x} \cdot \vec{y}| $ ---- $|\vec{A}\cdot\vec{B}|^2\le(\vec{A}\cdot\vec{A})(\vec{B}\cdot\vec{B})$ ---- Up: [[부등식,inequality]]